Sable - Ticked
called
"RED"
AT BIRTH

The picture was taken 30 minutes after the last pup was whelped.  
Notice the only pigment (color) visible are the facial markings and one
pup has a spot on the loin area.  

With the exception of any facial markings or body spots, ACD's are born
white (due to the extreme pie bald gene, "s^w").  Body spots are due to
the piebald gene, "s^p".  They start to color out at around 3 weeks of
age.  Some color out a little sooner, some a little later.  This coloring
continues sometimes until the puppy is past 6 months old.  Some
owners have said their ACD grew darker or lighter until they were past 6
years of age.
SABLE - RED
The "red" ACD is genetically a sable ("a^y").















The genes involved in a "red" ACD and ASTCD are (I will talk about what could
be present on another page):

E Locus : E -- extension of eumelanin or phaeomelanin in coat
B Locus : B -- black pigment, acting only on eumelanin (black/brown)
D Locus : D -- full color, not dilute
C Locus : C -- full color, not dilute
A Locus : a^y -- sable
K Locus : k -- non dominant, non-brindle, allows A Locus alleles to be expressed.
T Locus : T -- ticked (pigmented hairs in an otherwise white coat)
S Locus : s^w -- extreme white, dogs that also have body spots are said to also be s^p -- piebald
G Locus : g -- non-graying
M Locus : m -- non-merle (ACD's are not merled)

A typical "red" ACD may have a genotype that looked like this:
E/E B/B D/D C/C a^y/a^y k/k T/T s^w/s^w g/g m/m

OR: if they had body spots -- s^p/s^w, instead of s^w/s^w

When one parent is "ticked-black/tan", the genotype will look like this:
E/E B/B D/D C/C a^y/a^t k/k T/T s^w/s^w g/g m/m

Every gene is the same as with the "ticked-black/tan" ACD, with the exception of the alleles located on the A
Locus.  The "red" ACD is a^y, meaning sable.  When one parent is "ticked-black/tan" and one is "red", the
offspring receives a copy of the tan point gene from the "ticked-black/tan" parent and a copy of the sable gene
from the "red" parent.  The genotype now looks like:  a^y/a^t --- sable is incompletely dominant to tan points, so the
puppy will be red, but because of the a^t, the coloration will have a black overlay.  

Incompletely dominant means that one allele does not completely dominant another --- both colors can be
expressed.